🐛 Fixes
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		| @@ -175,7 +175,7 @@ class SolverService { | ||||
|       CalculationStep( | ||||
|         title: '第二步:选择解法', | ||||
|         explanation: '无法进行因式分解,我们选择使用求根公式法。', | ||||
|         formula: r'\$\$\Delta = b^2 - 4ac\$\$', | ||||
|         formula: '\$\$\\Delta = b^2 - 4ac\$\$', | ||||
|       ), | ||||
|     ); | ||||
|  | ||||
| @@ -184,8 +184,8 @@ class SolverService { | ||||
|       CalculationStep( | ||||
|         title: '第三步:计算判别式 (Delta)', | ||||
|         explanation: | ||||
|             '\$\$\Delta = b^2 - 4ac = ($b)^2 - 4 \cdot ($a) \cdot ($c) = $delta\$\$', | ||||
|         formula: '\$\$\Delta = $delta\$\$', | ||||
|             '\$\$\\Delta = b^2 - 4ac = ($b)^2 - 4 \\cdot ($a) \\cdot ($c) = $delta\$\$', | ||||
|         formula: '\$\$\\Delta = $delta\$\$', | ||||
|       ), | ||||
|     ); | ||||
|  | ||||
| @@ -198,13 +198,13 @@ class SolverService { | ||||
|           explanation: | ||||
|               r'因为 $\Delta > 0$,方程有两个不相等的实数根。公式: $x = \frac{-b \pm \sqrt{\Delta}}{2a}$。', | ||||
|           formula: | ||||
|               '\$\$x_1 = ${x1.toStringAsFixed(4)}, \quad x_2 = ${x2.toStringAsFixed(4)}\$\$', | ||||
|               '\$\$x_1 = ${x1.toStringAsFixed(4)}, \\quad x_2 = ${x2.toStringAsFixed(4)}\$\$', | ||||
|         ), | ||||
|       ); | ||||
|       return CalculationResult( | ||||
|         steps: steps, | ||||
|         finalAnswer: | ||||
|             '\$\$x_1 = ${x1.toStringAsFixed(4)}, \quad x_2 = ${x2.toStringAsFixed(4)}\$\$', | ||||
|             '\$\$x_1 = ${x1.toStringAsFixed(4)}, \\quad x_2 = ${x2.toStringAsFixed(4)}\$\$', | ||||
|       ); | ||||
|     } else if (delta == 0) { | ||||
|       final x = -b / (2 * a); | ||||
| @@ -250,7 +250,7 @@ class SolverService { | ||||
|         formula: | ||||
|             ''' | ||||
|  | ||||
| egin{cases} | ||||
| \\begin{cases} | ||||
| ${a1}x ${b1 >= 0 ? '+' : ''} ${b1}y = $c1 & (1) \\ | ||||
| ${a2}x ${b2 >= 0 ? '+' : ''} ${b2}y = $c2 & (2) | ||||
| \\end{cases} | ||||
| @@ -277,7 +277,7 @@ ${a2}x ${b2 >= 0 ? '+' : ''} ${b2}y = $c2 & (2) | ||||
|         formula: | ||||
|             ''' | ||||
|  | ||||
| egin{cases} | ||||
| \\begin{cases} | ||||
| ${newA1}x ${b1 * b2 >= 0 ? '+' : ''} ${b1 * b2}y = $newC1 & (3) \\ | ||||
| ${newA2}x ${b1 * b2 >= 0 ? '+' : ''} ${b1 * b2}y = $newC2 & (4) | ||||
| \\end{cases} | ||||
|   | ||||
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